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Implied LGD from bond rates (Question 9)
Posted: 03 July 2009 02:17 PM   Ignore ]  
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This is a good sample question from GARP: first, it is not too easy and not too hard; this IMO is about typical of the exam’s difficulty and (ii) it does not favor formula memorization: the cited reference is de Servigny, but I do not think you will find the formula in the referenced reading. A formula is not needed, we can apply logic and yet another instance of a no-arbitrage idea - David

Question

Full E1.09. Suppose the rate on Company A’s one-year zero-coupon bond is 10.0% and the one-year T-bill rate is 8.0%. Assume the T-bill is riskless and the probability of default of Company A’s bond is 10%. What is the LGD of Company A’s bond?

a. 18.18%
b. 81.82%
c. 20.01%
d. 79.99%

[my adds next, let’s beat this up!]

9b. [hard] Assume instead we are given that the LGD of Company’s A’s bond is 75% (using Basel II LGD for junior debt under foundation IRB approach). Assuming the credit spread remains 2% (10% - 8%), what is the implied probability of default (PD)?

9c. The answer assumes annual compounding. If we instead assume continuous compounding (i.e., risky bond returns 10% continuous and T-bill returns 8% continuous), what is the implied loss given default (LGD)?. Notice that compounding matters; semi-annual compounding would give a slightly different result.

9d. [hard] As Saunders writes, “Collateral requirements are a method of controlling default risk; they act as a direct substitute for risk premiums in setting required loan rates.” Let collateral (recovery) = 1 - Loss given default (LGD) and solve for the credit spread as a function of the probability of default (PD) and the recovery (c).

9e. Which continuous probability distribution—that is reviewed in the assigned Rachev (Fat-tailed and Skewed Asset Return Distributions)—are we most likely to find in use to characterize the loss given default (LGD) or recovery function?

9f. How are recovery rates (1-LGD) estimated?

9g. What are the most important determinants of recovery/LGD?

Answers:

9a.
An investor should be indifferent between:
(i) invest in riskless T-bill, or
(ii) invest in risky bond

Such that, if k = risky return and i = riskless return (using Saunders’ notation)
1+i = (probability of repayment * return if repayment) + (probability of default * return if default); i.e., weighted average return
1+i = [(1-PD) * (1+k)] + [PD*(1+k)*(1-LGD)]; i.e., we recover 1-LGD

solve for LGD:
1+i = [(1-PD) * (1+k)] + [PD*(1+k)*(1-LGD)]
PD*(1+k)*(1-LGD) = (1+i) - [(1-PD) * (1+k)]
(1-LGD) = (1+i) - [(1-PD) * (1+k)] / (PD*(1+k))
LGD = 1- [(1+i) - [(1-PD) * (1+k)] / (PD*(1+k))]

and here:
LGD = 1- [(1+8%) - [(1-10%) * (1+10%)] / 10%*(1+10%)] = 18.18%

9b. [hard] Assume instead we are given that the LGD of Company’s A’s bond is 75% (using Basel II LGD for junior debt under foundation IRB approach). Assuming the credit spread remains 2% (10% - 8%), what is the implied probability of default (PD)?

Instead solve for PD:
1+i = [(1-PD) * (1+k)] + [PD*(1+k)*(1-LGD)]
I get PD = 2.42%

9c. The answer assumes annual compounding. If we instead assume continuous compounding (i.e., risky bond returns 10% continuous and T-bill returns 8% continuous), what is the implied loss given default (LGD)?. Notice that compounding matters; semi-annual compounding would give a slightly different result.

The no-arbitage indifference is now:
EXP(i) = (1-PD)*EXP[k] + PD*EXP[k]*(1-LGD)
solving for PD, I get 19.8%

9d. [hard] As Saunders writes, “Collateral requirements are a method of controlling default risk; they act as a direct substitute for risk premiums in setting required loan rates.” Let collateral (recovery) = 1 - Loss given default (LGD) and solve for the credit spread as a function of the probability of default (PD) and the recovery (c).

1+i = [(1-PD) * (1+k)] + [PD*(1+k)*(1-LGD)]—>
1+i = (1+k)*[(1-PD) + [PD*(1-LGD)]
...divide both sides by [(1-PD) + [PD*(1-LGD)]:
(1+i)/[(1-PD) + [PD*(1-LGD)] = (1+k)
...since we want the spread (k-i), subtract (1-i) from both sides:
(1+i)/[(1-PD) + [PD*(1-LGD)] - (1+ i) = (1+k) - (1+i), or
(1+k) - (1+i) = k-i = (1+i)/[(1-PD) + [PD*(1-LGD)] - (1+i)
note: Saunders gives an equivalent expression where p = prob of repayment = 1- PD and gamma = recovery = 1 - LGD
so that that above: (1+k) - (1+i) = k-i = (1+i)/[(1-PD) + [PD*(1-LGD)] - (1+i)
= k-i = (1+i)/[gamma + p - p*gamma] - (1+i); Saunder’s version

9e. Which continuous probability distribution—that is reviewed in the assigned Rachev (Fat-tailed and Skewed Asset Return Distributions)—are we most likely to find in use to characterize the loss given default (LGD) or recovery function?

Beta distribution (flexible)

9f. How are recovery rates (1-LGD) estimated?

Postdefault prices (if possible) or estimated recovery (e.g., PV of estimated cash flows)

9g. What are the most important determinants of recovery/LGD?

Seniority (arguably most important, but the others are not in any order)
Collateral
Macroeconomy & Business cycle (systemic risks)
Industry

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Posted: 25 October 2009 08:13 AM   Ignore ]   [ # 1 ]  
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Hi David,

Reference:
1+i = [(1-PD) * (1+k)] + [PD*(1+k)*(1-LGD)]—>————————————(Step 1)
1+i = (1+k)[(1-PD) + [PD*(1-LGD)] such that ————————————-  (step 2)
(1+k) - (1+i) = k-i = (1+i)/[(1-PD) + [PD*(1-LGD)] - (1+i) ——————-(step 3)

I can not follow step 2 and step 3.  Could you show the mathematics working between step 2 and step 3?

Thanks
Learning

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Posted: 25 October 2009 12:22 PM   Ignore ]   [ # 2 ]  
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Hi Learning - sure thing, I added the in-between steps above (and inserted the Saunder’s version, which is the same, except gamma = recovery = 1-LGD and p = prob of repay = 1- PD)...thanks, David

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Posted: 01 November 2009 07:14 PM   Ignore ]   [ # 3 ]  
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Hi David,

I wonder when I should use spread to calculate LGD:
LGD = spead/PD = (10-2)/10 = 20%
?

For example Full II question 2:
The risk-free rate is 5% per year and a corporate bond yields 6% per year. Assuming a recovery rate of 75% on the corporate bond, what is the approximate market implied one-year probability of default of the corporate bond?
a. 1.33% b. 4.00% c. 8.00% d. 1.60%
CORRECT: B Using the approximation method, the 1‐year probability of default is (6%‐5%)/(1‐0.75) = 4%

Does it mean we need to VERY careful about “approximate”?

Thanks.

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Posted: 11 November 2009 08:59 AM   Ignore ]   [ # 4 ]  
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ajsa is totally correct. Technically, we could use the formula 1+i = [(1-PD) * (1+k)] + [PD*(1+k)*(1-LGD)]

If you do this, you arrive at a PD = .037736

While clearly not the same formula as PD = spread/LGD, there is no reason this formula should not give you the right answer. In fact, I am certain this formula gives you the right answer while the shorter one gives you an approximation. Considert the explanation David provided and it is clear the longer equation is more granular. In my opinion, this is one of many examples in the FRM where an answer seems a bit arbitrary. Add to that, variance of terminology/notation that aims to explain the same concept. A bit bloated in my opinion.

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Posted: 11 November 2009 09:06 AM   Ignore ]   [ # 5 ]  
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FoQ -
Yea, ajsa’s had an eagle eye all year…
My view on this is here: http://www.bionicturtle.com/forum/viewthread/2158/
I totally agree, the “Saunder’s version” is more granular/accurate, but at the same time the Hull was just added in 2009, creating a definitional conflict…David

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