dS/S = d Log(S) ?

itsyourz

New Member
Hi,

in 06 practice exam set I , number 40.

about Geometric Brown Motion.

I know S is lognormally distributed and then ln(S) is normally distributed

how come is dS/S normally distributed?

it says dS/S equals to d ln(S)

is it mathmatically equal?
 
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