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# Expected Shortfall from frequency and severity distribution table

#### delta123

##### New Member
FRM 2012  PART 1: MOCK EXAM D  22
www.bionicturtle.com Question 13:
13. For a certain operational process, the frequency distribution below implies a 20% probability of two (2) loss events during the month. For each loss event that occurs, the severity distribution is given by: 50% probability of $1,000 loss (i.e., the loss amount conditional on a loss occurrence), 20% probability of$10,000 loss, and 10% probability of $100,000 loss: Assuming the frequency and severity are independent, what is the 99.0% monthly expected shortfall (ES) of the aggregate (tabulated) loss? a)$110,000
b) $128,000 c)$140,000
d) $200,000 Answer & Explanation: 13. B.$128,000
The worst loss of $200,000 occurs with p.d.f. probability of 20%*10%*10% = 0.20%. The next worse loss of$110,000 occurs with p.d.f. probability of 20%*10*20% + 20%*20*10% = 0.40% + 0.40% = 0.80%; this total loss counts twice because, order matters, and we can experience either a $10,000 loss followed by a$100,000 loss, or a $100,000 loss followed by a$10,000 loss.
These two loss amounts constitute the 1.0% tail (0.20% + 0.80%) and:
The average loss (conditional on the loss exceeding 99%) = ($200,000*0.20% +$110,000*0.80%)/1% = \$128,000; i.e., the weighted average of this 1% loss tail.

Can someone help me understand the calculation or point to a video/link. Appreciate it.

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