Hi,
exp(.95%*5)=(exp(5))^.95%=148.41^.95%
Let x= 148.41^.95%
Take log both sudes
log(x)=log(148.41^.95% )=.95%log148.41
Find rhs from log table,
Then find antilog of obtained rhs value,then this antilog is x the value we yearned for.
Thanks
exp(.95%*5)=(exp(5))^.95%=148.41^.95%
Let x= 148.41^.95%
Take log both sudes
log(x)=log(148.41^.95% )=.95%log148.41
Find rhs from log table,
Then find antilog of obtained rhs value,then this antilog is x the value we yearned for.
Thanks